Compound states [like (s) (aq) or (g)] are not required. Example for ionic nature in molten salt solution molten $\ce{NaCl}$: Direct electrochemical power generation from carbon in fuel cells with molten sodium hydroxide: Chemical Engineering Communications, 2005, 192 (12), 1655-1670. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. Two good references to address this question are: DETERMINATION OF THE SOLUBILITY OF OXYGEN BEARING That's what I'd expect to happen. These two atoms combine with the oxygen from the NaOH to form H2O, which is the chemical formula for water. From the electrode materials investigated—$\ce{Pt}$, $\ce{Au}$, $\ce{Ag}$, $\ce{Ni}$ and $\ce{Fe}$—the last one only exhibits a positive potential shift by comparison to the other metals; this shift has been interpreted in terms of an $\ce{O2^{2-}}$ impoverishment following corrosion. Mush. \ce{CH3OH + Na &-> CH3ONa + H2}\\ In many cases a complete equation will be suggested. Examples: Fe, Au, Co, Br, C, O, N, F.     Compare: Co - cobalt and CO - carbon monoxide, To enter an electron into a chemical equation use {-} or e. To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. At $\ce{400 ^\circ C}$, under vacuum distillation conditions: The equilibrium oxide in a sodium-potassium ($\ce{NaK}$)-oxygen system is sodium monoxide. Will 5G Impact Our Cell Phone Plans (or Our Health?! is answered in Wikipedia: yes. Is the Coronavirus Crisis Increasing America's Drug Overdoses? Enter either the number of moles or weight for one of the compounds to compute the rest. By using this website, you signify your acceptance of, calcium hydroxide + carbon dioxide = calcium carbonate + water, Enter an equation of a chemical reaction and click 'Balance'. Same through for water, at first, oxygen has two covalent bonds with two hydrogens. This is a redox reaction regardless of what species $\ce{K}$ would react with. Answer to situation (b) is a little complicated than this. Potassium ionic radii ($\pu{280 pm}$) and sodium ionic radii ($\pu{227 pm}$) seem quite different. Auch in Praktika der Oberstufe empfiehlt sich der Einsatz von verdünnten Lösungen. suggests two products, but the real question is whether any reaction will occur. Do metals react with ammonia gas (not liquid phase)? \begin{align} The ionic conductivity of molten $\ce{NaOH}$ exceeds that of molten sodium carbonate by a factor of 1.5 [1]. Does $\ce{NaOH + Na}$ form $\ce{Na2O}$? The comment about using molten potassium to react with $\ce{KOH}$ (and presumably liquid sodium to react with $\ce{NaOH}$) suggests that simply pushing a solid hydroxide against a solid metal might not give a rapid reaction. Fachsemester Pharmazie Seite 6 Seite 6 3. A. protons B. It makes unlikely to see its solid as $\ce{NaKO}$ or $\ce{NaOK}$, and there would be no such product in liquid reaction if lattice energy does not stabilize possible end product. The only way I can think of to get your reaction to go forward would be to have the molten forms of $\ce{NaOH}$ and $\ce{K}$, which would react like this: $\ce{NaOH}$ reacts with $\ce{K}$ to form $\ce{KOH}$ In short, I expect sodium displacement by potassium, not another oxygen reduction. Making statements based on opinion; back them up with references or personal experience. Find your cations and anions in each compound. Say it $\ce{M-OH}$, this will be $\ce{M+ + OH-}$ in solution, and adding another alkali metal will not have any effect on them, $\ce{OH-}$ is quite stable in this condition, likewise $\ce{M+}$. The rate law for the reaction: RCl + NaOH → ROH + NaCl is given by;. This reaction takes place at a temperature of 380-450°C. You understood right, but I wanted to begin from that to explain why what was asked is not likely. Enter an equation of a chemical reaction and click 'Balance'. Here k(T) is the reaction rate constant that depends on temperature, and [A] and [B] are the molar concentrations of substances A and B in moles per unit volume of solution, assuming the reaction is taking place throughout the volume of the solution. To determine how much reaction occurs we need to set up an ICE 'like' table. K(NaOH) 2: 1: 119.09251856: OH: 1: 17.00734: Units: molar mass - g/mol, weight - g. Please tell about this free chemistry software to your friends! $\ce{Na2O}$ is Sodium oxide, which is like anhydrous form of $\ce{NaOH}$. Would it be reasonable for my manager to state "I ignore emails" as a negative in a performance review? Picture of reaction: Сoding to search: KOH + Na cnd [ temp ] = NaOH + K. Asking for help, clarification, or responding to other answers. Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers, and students in the field of chemistry. Would this 5.5V transient voltage suppressor be damaged at 15V? There is no compound like NaOK? So I am just wondering is that always true? The peroxide which is required for the corrosion reactions can be formed only by chemical reaction of the melt with $\ce{O2}$ , not, however, by anodic oxidation, because peroxide oxidation essentially precedes the oxidation of hydroxyl ions yielding oxygen and water vapour. Substitute immutable groups in chemical compounds to avoid ambiguity. Festival of Sacrifice: The Past and Present of the Islamic Holiday of Eid al-Adha. Thus, it is safe to assume that molten $\ce{NaOH}$ functions as $\ce{Na+}$ and $\ce{OH-}$ ions in molten state. In many cases a complete equation will be suggested. The equation K + NaOH => Na + KOH should it react, true or false? Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide; To enter an electron into a chemical equation use {-} or e (Interestingly, at the halfway point, you have $\ce{NaK}$ alloy, which is extremely reactive!). The last question (Does $\ce{NaOH + Na}$ form $\ce{Na2O}$?) \begin{align} So, you are suggesting that both pathways - removal of sodium and removal of hydrogen - will give $\ce{NaOK}$ - or as you say - the mixture $\ce{Na2O}$ and $\ce{K2O}$? The essential reaction is elimination of hydrogen, which is not energetically favored, but which drives the reaction by eliminating the reverse reaction ($\ce{H2 + Na2O -> 2 NaOH}$ or $\ce{H2 + K2O -> 2 KOH}$). What does commonwealth mean in US English? Electrolysis of aqueous copper (II) nitrate. Answer to situation (a) is potassium would essentially react with water (other ions in the solution are $\ce{Na+}$ and $\ce{OH-}$) based on standard potentials of following possible half-reactions. Im Labor wird Natronlauge unter starker Wärmeentwicklung durch Lösen von, Natronlauge ist ein bedeutender Rohstoff zur. H is 1+ Cl is 1- K is 1+ OH (hydroxide) is 1- NO3 (nitrate) is 1- Na is 1+ Since they all have a charge of 1 +/-, the reactions will be straightforward.